200+ câu Trắc nghiệm Điều khiển số có đáp án - Phần 8

A. \(W(z)=\frac{D\left. z \right.G(z)}{1+D\left. z \right.G(z)}\)

B. \(W(z)=\frac{D\left. z \right.G(z)}{1-D\left. z \right.G(z)}\)

C. \(W(z)=\frac{1+D\left. z \right.G(z)}{D\left. z \right.G(z)}\)

D. \(W(z)=\frac{1-D\left. z \right.G(z)}{D\left. z \right.G(z)}\)

A. \(D\left. z \right.=\frac{1}{G(z)}\frac{W(z)}{1-W(z)}\)

B. \(D\left. z \right.=\frac{1}{G(z)}\frac{W(z)}{1+W(z)}\)

C. \(D\left. z \right.=-\frac{1}{G(z)}\frac{W(z)}{1+W(z)}\)

D. Tất cả A, B, C đều sai

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\({G}_{D}\left. z \right.=\frac{{K}_{D}}{T}\frac{z-1}{z}\)

\({G}_{D}\left. z \right.=\frac{T}{{K}_{D}}\frac{z-1}{z}\)

\({G}_{D}\left. z \right.=\frac{T}{{K}_{D}}\frac{z+1}{z}\)

\({G}_{D}\left. z \right.=\frac{T}{{K}_{D}}\frac{z+1}{z}\)

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\({G}_{1}\left. z \right.=\frac{{K}_{1}T}{2}\frac{z+1}{z-1}\)

\({G}_{1}\left. z \right.=\frac{{K}_{1}T}{2}\frac{z-1}{z+1}\)

\({G}_{1}\left. z \right.=\frac{2}{{K}_{1}T}\frac{z-1}{z+1}\)

\({G}_{1}\left. z \right.=\frac{2}{{K}_{1}T}\frac{z+1}{z-1}\)

\({G}_{PI}\left. z \right.={K}_{P}+\frac{{K}_{1}T}{2}\frac{z+1}{z-1}\)

\({G}_{PI}\left. z \right.={K}_{P}-\frac{{K}_{1}T}{2}\frac{z+1}{z-1}\)

\({G}_{PI}\left. z \right.={K}_{P}-\frac{2}{{K}_{1}T}\frac{z+1}{z-1}\)

\({G}_{PI}\left. z \right.={K}_{P}+\frac{2}{{K}_{1}T}\frac{z+1}{z-1}\)

\({G}_{PD}\left. z \right.={K}_{P}+\frac{{K}_{D}}{T}\frac{z-1}{z}\)

\({G}_{PD}\left. z \right.={K}_{P}-\frac{{K}_{D}}{T}\frac{z-1}{z}\)

\({G}_{PD}\left. z \right.={K}_{P}-\frac{T}{{K}_{D}}\frac{z-1}{z}\)

\({G}_{PD}\left. z \right.={K}_{P}+\frac{T}{{K}_{D}}\frac{z-1}{z}\)

\({G}_{PID}\left. z \right.={K}_{P}+\frac{{K}_{1}T}{2}\frac{z+1}{z-1}+\frac{{K}_{D}}{T}\frac{z-1}{z}\)

\({G}_{PID}\left. z \right.={K}_{P}+\frac{{K}_{1}T}{2}\frac{z+1}{z-1}-\frac{{K}_{D}}{T}\frac{z-1}{z}\)

\({G}_{PID}\left. z \right.={K}_{P}-\frac{{K}_{1}T}{2}\frac{z+1}{z-1}-\frac{{K}_{D}}{T}\frac{z-1}{z}\)

\({G}_{PID}\left. z \right.=-{K}_{P}-\frac{{K}_{1}T}{2}\frac{z+1}{z-1}-\frac{{K}_{D}}{T}\frac{z-1}{z}\)

Sai phân lùi

Sai phân giữa

Sai phân tới

Tất cả A, B, C đều sai

Tích phân hình thang

Tích phân hình chữ nhật lùi

Tích phân hình chữ nhật tới

Tất cả đều sai

\({G}_{c}\left. z \right.=K\frac{\left. aT+2 \right.z+(aT-2)}{\left. bT+2 \right.z+(bT-2)}\)

\({G}_{c}\left. z \right.=K\frac{\left. aT+2 \right.z-(aT-2)}{\left. bT+2 \right.z+(bT-2)}\)

\({G}_{c}\left. z \right.=K\frac{\left. aT+2 \right.z-(aT-2)}{\left. bT+2 \right.z-(bT-2)}\)

\({G}_{c}\left. z \right.=-K\frac{\left. aT+2 \right.z+(aT-2)}{\left. bT+2 \right.z+(bT-2)}\)

C. |z_C| > 1 và |p_C| > 1

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\({G}_{c}\left. z \right.={K}_{C}\frac{z+{z}_{c}}{z+{p}_{c}}\)

\({G}_{c}\left. z \right.={K}_{C}\frac{z-{z}_{c}}{z+{p}_{c}}\)

\({G}_{c}\left. z \right.={K}_{C}\frac{z-{z}_{c}}{z-{p}_{c}}\)

\({G}_{c}\left. z \right.=-{K}_{C}\frac{z+{z}_{c}}{z+{p}_{c}}\)

A. K_C=1

B. K_C=1.24

C. K_C=0

D. K_C=2

A. \({G}_{C}\left. z \right.=1.24\frac{z-0.607}{z-0.029}\)

B. \({G}_{C}\left. z \right.=1.24\frac{z+0.607}{z-0.029}\)

C. \({G}_{C}\left. z \right.=1.24\frac{z+0.607}{z+0.029}\)

D. \({G}_{C}\left. z \right.=-1.24\frac{z-0.607}{z-0.029}\)

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A. \({K}_{C}≈1\)

B. \({K}_{C}=2\)

C. \({K}_{C}=0\)

D. \({K}_{C}=3\)

A. \({G}_{c}\left. z \right.=\frac{z-0.99}{z-0.999}\)

B. \({G}_{c}\left. z \right.=\frac{z+0.99}{z-0.999}\)

C. \({G}_{c}\left. z \right.=\frac{z+0.99}{z+0.999}\)

D. \({G}_{c}\left. z \right.=-\frac{z+0.99}{z+0.999}\)