15 câu Trắc nghiệm Một số phương trình lượng giác thường gặp có đáp án (Thông hiểu)

A. $x=\pm \frac{\pi }{6}+k\pi \left(k\in Z\right)$

B. $x=\pm \frac{\pi }{6}+k\pi \left(k\in Z\right)$

C. $x=\pm \frac{\pi }{3}+k\pi \left(k\in Z\right)$

D. $\left[\begin{array}{l}x=\frac{\pi }{6}+k\pi (k\in Z)\\ x=\frac{\pi }{3}+k\pi (k\in Z)\end{array}\right.$ 

A. $x=\pm \frac{2\pi }{3}+k2\pi \left(k\in Z\right)$

B. $x=\pm \frac{\pi }{2}+k2\pi \left(k\in Z\right)$

C. $x=\pm \frac{\pi }{3}+k2\pi \left(k\in Z\right)$

D. $x=\frac{2\pi }{3}+k2\pi \left(k\in Z\right)$ 

A. $\frac{3\pi }{5}$

B. $\frac{29\pi }{30}$

C. $\frac{5\pi }{6}$

D. $\frac{23\pi }{30}$ 

A. $\left[\begin{array}{l}x=-\frac{\pi }{6}+\frac{k2\pi }{9}\\ x=\frac{7\pi }{6}+\frac{k2\pi }{9}\end{array}\right.(k\in Z)$

B. $\left[\begin{array}{l}x=-\frac{\pi }{9}+\frac{k2\pi }{9}\\ x=\frac{7\pi }{9}+\frac{k2\pi }{9}\end{array}\right.(k\in Z)$

C. $\left[\begin{array}{l}x=-\frac{\pi }{12}+\frac{k2\pi }{9}\\ x=\frac{7\pi }{12}+\frac{k2\pi }{9}\end{array}\right.(k\in Z)$

D. $\left[\begin{array}{l}x=-\frac{\pi }{54}+\frac{k2\pi }{9}\\ x=\frac{\pi }{18}+\frac{k2\pi }{9}\end{array}\right.(k\in Z)$ 

A. 1

B. 2

C. 3

D. Vô nghiệm

A. $x=k\pi \left(k\in \mathbb{Z}\right)$

B. $x=\frac{\mathrm{\pi }}{2}+k\pi \left(k\in \mathbb{Z}\right)$

C. $x=\frac{\pi }{6}+k2\pi \left(k\in \mathbb{Z}\right)$ 

D. Tất cả đều đúng

A. $\left[\begin{array}{l}x=\frac{\pi }{6}+k2\pi \\ x=\frac{\pi }{3}+k2\pi \end{array}\right.(k\in Z)$

B. $\left[\begin{array}{l}x=\frac{5\pi }{6}+k\pi \\ x=\frac{\pi }{3}+k2\pi \end{array}\right.(k\in Z)$

C. $\left[\begin{array}{l}x=\frac{5\pi }{6}+k2\pi \\ x=\frac{\pi }{3}+k2\pi \end{array}\right.(k\in Z)$

D. $\left[\begin{array}{l}x=\frac{5\pi }{6}+k\pi \\ x=\frac{\pi }{3}+k\pi \end{array}\right.(k\in Z)$ 

A. Có 1 họ nghiệm 

B. Có 2 họ nghiệm 

C. Vô nghiệm 

D. Có 1 nghiệm duy nhất 

A. $\left[\begin{array}{l}x=-\frac{\pi }{18}+\frac{k2\pi }{3}\\ x=\frac{3\pi }{10}+\frac{k2\pi }{5}\end{array}\right.(k\in Z)$

B. $\left[\begin{array}{l}x=\frac{\pi }{18}+\frac{k2\pi }{3}\\ x=-\frac{3\pi }{10}+\frac{k2\pi }{5}\end{array}\right.(k\in Z)$

C. $\left[\begin{array}{l}x=-\frac{\pi }{18}+\frac{k2\pi }{5}\\ x=\frac{3\pi }{10}+\frac{k2\pi }{3}\end{array}\right.(k\in Z)$

D. $\left[\begin{array}{l}x=\frac{\pi }{18}+\frac{k2\pi }{3}\\ x=\frac{3\pi }{10}+\frac{k2\pi }{5}\end{array}\right.(k\in Z)$ 

A. $\left[\begin{array}{l}x=\frac{\pi }{2}+k\pi \\ x=\frac{\pi }{6}+k\pi \end{array}\right.(k\in Z)$

B. $\left[\begin{array}{l}x=\frac{\pi }{4}+k\pi \\ x=\frac{\pi }{3}+k\pi \end{array}\right.(k\in Z)$

C. $\left[\begin{array}{l}x=\frac{\pi }{8}+k2\pi \\ x=\frac{\pi }{12}+k2\pi \end{array}\right.(k\in Z)$

D. $\left[\begin{array}{l}x=\frac{\pi }{8}+k\pi \\ x=\frac{\pi }{12}+k\pi \end{array}\right.(k\in Z)$ 

A. $x=\frac{\pi }{2}+k\pi \left(k\in Z\right)$

B. $\left[\begin{array}{l}x=\frac{\pi }{4}+k\pi \\ x=arctan(-2)+k\pi \end{array}\right.(k\in Z)$

C. $x=-\frac{\pi }{4}+k\pi \left(k\in Z\right)$ 

D. Vô nghiệm 

A. 0

B. 1

C. 2

D. 3

A. $\left[\begin{array}{c}x=\frac{\mathrm{\pi }}{3}+k\mathrm{\pi }\\ x=\frac{5\mathrm{\pi }}{3}+k\mathrm{\pi }\end{array}\right.$

B. $\left[\begin{array}{c}x=\frac{\mathrm{\pi }}{4}+k\mathrm{\pi }\\ x=5\mathrm{\pi }+k\mathrm{\pi }\end{array}\right.$

C. $\left[\begin{array}{c}x=\frac{\mathrm{\pi }}{6}+k\mathrm{\pi }\\ x=\frac{5\mathrm{\pi }}{4}+k\mathrm{\pi }\end{array}\right.$

D. $\left[\begin{array}{c}x=\frac{\mathrm{\pi }}{12}+k\mathrm{\pi }\\ x=\frac{5\mathrm{\pi }}{12}+k\mathrm{\pi }\end{array}\right.$ 

A. $\mathrm{x}=\frac{\mathrm{\pi }}{3}+\mathrm{k\pi }, \mathrm{x}=\mathrm{k\pi }, \mathrm{x}=\frac{\mathrm{k\pi }}{5}$

B. $\mathrm{x}=\frac{\mathrm{\pi }}{2}+\mathrm{k\pi }, \mathrm{x}=k2\pi , \mathrm{x}=\frac{2\mathrm{k\pi }}{5}$

C. $\mathrm{x}=\frac{\mathrm{\pi }}{2}+2\mathrm{k\pi }, \mathrm{x}=\frac{k2\pi }{3}$

D. $\mathrm{x}=\pm \frac{\mathrm{\pi }}{2}+\mathrm{k\pi }, \mathrm{x}=k2\pi$ 

A. $x=\frac{\mathrm{\pi }}{9}+\frac{k2\mathrm{\pi }}{3} \left(k\in Z\right)$

B. $x=\frac{\mathrm{\pi }}{18}+\frac{k\mathrm{\pi }}{6} \left(k\in Z\right)$

C. $x=\pm \frac{\mathrm{\pi }}{6}+\frac{k\mathrm{\pi }}{2} \left(k\in Z\right)$

D. $x=\frac{\mathrm{\pi }}{18}+\frac{k2\mathrm{\pi }}{3}; x=-\frac{\mathrm{\pi }}{6}+\frac{k\mathrm{\pi }}{2} \left(k\in Z\right)$