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A.a > 0 

B.a = 0 

C.\[a \ne 0\;\;{\rm{ }}\;{\rm{ }}\;\;\]

D.a < 0 

A.\[{a^{\frac{m}{n}}} = \sqrt[n]{{{a^m}}}\]

B. \[{a^{\frac{m}{n}}} = \sqrt[m]{{{a^n}}}\]

C. \[{a^{\frac{m}{n}}} = \sqrt[{mn}]{a}\]

D. \[{a^{\frac{m}{n}}} = \sqrt[m]{{{a^{mn}}}}\]

A.\[{a^{\frac{1}{n}}} = \sqrt[n]{a}\]

B. \[{a^{\frac{1}{n}}} = \sqrt {{a^n}} \]

C. \[{a^{\frac{1}{n}}} = {a^n}\]

D. \[{a^{\frac{1}{n}}} = \sqrt[a]{n}\]

A.\[{a^{m.n}} = {a^m}.{a^n}\]

B.\[{a^{mn}} = {a^m} + {a^n}\]

C. \[{a^{mn}} = {a^m}:{a^n}\]

D. \[{a^{mn}} = {\left( {{a^m}} \right)^n}\]

A.\[{a^m} > 1\]

B. \[{a^m} = 1\]

C. \[{a^m} < 1\]

D. \[{a^m} > 2\]

A.\[{a^m} < {b^m}\]

B. \[{a^m} > {b^m}\]

C. \[1 < {a^m} < {b^m}\]

D. \[{a^m} > {b^m} > 1\]

A.\[{a^m} > {b^m} > 1\]

B. \[1 < {a^m} < {b^m}\]

C. \[{a^m} < {b^m} < 1\]

D. \[1 > {a^m} > {b^m}\]

A.\[{b^n} = a\]

B. \[{a^n} = b\]

C. \[{a^n} = {b^n}\]

D. \[{n^a} = b\]

A.\[{\left( {\frac{3}{4}} \right)^m} > {\left( {\frac{1}{2}} \right)^m}\]

B. \[1 < {\left( {\frac{4}{3}} \right)^m}\]

C. \[{\left( {\frac{2}{3}} \right)^m} < {\left( {\frac{3}{4}} \right)^m}\]

D. \[{\left( {\frac{{13}}{7}} \right)^m} > {2^m}\]

A.\[{a^m} > {a^n} \Leftrightarrow m > n\]

B. \[{a^m} > {a^n} \Leftrightarrow m < n\]

C. \[{a^m} > {a^n} \Leftrightarrow m = n\]

D. \[{a^m} > {a^n} \Leftrightarrow m \le n\]

A.\[\sqrt[n]{{ab}} = \sqrt[n]{a}.\sqrt[n]{b}\]

B. \[\sqrt[n]{{{a^m}}} = \sqrt[n]{a}\sqrt[n]{m}\]

C. \[\sqrt[{mn}]{a} = \sqrt[n]{{{a^m}}}\]

D. \[\sqrt[n]{{\sqrt[m]{a}}} = \sqrt[n]{a}.\sqrt[m]{a}\]

A.\[\sqrt[{mn}]{a} = \sqrt[n]{a}\sqrt[m]{a}\]

B. \[\sqrt[{mn}]{a} = \sqrt[n]{{{a^m}}}\]

C. \[\sqrt[{mn}]{a} = \sqrt[m]{{{a^n}}}\]

D. \[\sqrt[{mn}]{a} = \sqrt[n]{{\sqrt[m]{a}}}\]

A.\[{\left( {\sqrt[{mn}]{a}} \right)^m} = \sqrt[n]{a}\]

B. \[\sqrt[{mn}]{{{a^m}}} = \sqrt[n]{a}\]

C. \[{\left( {\sqrt[{mn}]{{{a^m}}}} \right)^n} = a\]

D. \[{\left( {\sqrt[{mn}]{{{a^m}}}} \right)^n} = {a^n}\]

A.Nếu n chẵn thì \[\sqrt[n]{{{a^n}}} = a\]

B.Nếu n lẻ thì \[\sqrt[n]{{{a^n}}} = a\].

C.Nếu n chẵn thì \[\sqrt[n]{{{a^n}}} = - a\].            

D.Nếu n lẻ thì \[\sqrt[n]{{{a^n}}} = - a\].

A.a < 0            

B.a > 0            

C.\[a \in R\]

D. \[a \in Z\]

A.\[{a^n}\]

B. \[{b^n}\]

C. \[{a^\alpha }\]

D. \[{b^\alpha }\]

A.\[{\left( {{2^x}} \right)^y} = {2^{x + y}}\]

B. \[\frac{{{2^x}}}{{{2^y}}} = {2^{\frac{x}{y}}}\]

C. \[{2^x}{.2^y} = {2^{x + y}}\]

D. \[{\left( {\frac{2}{3}} \right)^x} = \frac{{{2^x}}}{{{3^y}}}\]

A.\[{2^{\sqrt x }} = {x^{\sqrt 2 }}\]

B. \[{3^{\sqrt {xy} }} = {\left( {{3^{\sqrt x }}} \right)^{\sqrt y }}\]

C. \[\frac{{{3^{\sqrt[3]{x}}}}}{{{3^{\sqrt[3]{y}}}}} = {3^{\sqrt[3]{{x - y}}}}\]

D. \[{x^{\sqrt 3 }} = {y^{\sqrt 3 }}\]

A.\[P = {x^{\frac{2}{{15}}}}\]

B. \[P = {x^{\frac{7}{{15}}}}\]

C. \[P = {x^{\frac{{38}}{{15}}}}\]

d. \[P = {x^{\frac{5}{2}}}\]

A.P=1

B. \[P = {b^{\frac{1}{{30}}}}\]

C. \[P = {b^{\frac{6}{5}}}\]

D. P=b